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In the orthonormal tetrad method, what is the relation between basis one forms and commutation coefficients?

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If $\omega_i$ are dual basis one forms corresponding to an orthonormal tetrad basis $e_i$, and given that the commutation coefficients $C_{ij}^k$ are defined by

\begin{equation}[e_i,e_j]=C_{ij}^k e_k\end{equation}

how do you prove the following equation

\begin{equation}\mathrm{d}\omega^a=-\frac{1}{2}C_{bc}^a\omega_b\wedge\omega_c\end{equation}

as given in equation 5.6, page 99 of "Relativity Demystified" by David McMahon, published by McGraw Hill, 2006, and where $\mathrm{d}$ is the exterior derivative operator?


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